IB=,dd +(I)  1Courier New1Symbol New1Courier New1Courier NewTimes New RomanTimes New Roman1Courier New1Courier New1Courier New1Courier NewP=PLSP=PLSP=PLSP=PLS?/ <```@@@?~~~~~ԱޱޱԱ޿޿ph (((Pdd{  d< p {2@@@???@@@@@@033333??@^ߛOw?HzG???m{n<G@l<@@?@ @@@6 | 8?@@@@@@@@@@@@2 2??@$$$@???????@Ldװpڰ4ذذhذ-dy = -deSeS2??h!@$$$Uy@???????LPTX\`dT(.0z5 D/(1-sin(t)),r = D/(1-sin(t)); 0.000000 <= t <= 6.2831902 2??@$$$@???????@x1`8<<dhlp Dܛx^2/(2*D)-D/2y = x^2/(2*D)-D/22???$$$????????  @$A(B,C0D4E00pi/4(x,y) = (0,0)2???$$$!@s=Ũ@????????!@s=Ũ@GHIJ\] ^|d*cos(a)/(1-sin(a))d*sin(a)/(1-sin(a))pi/42(x,y) = (d*cos(a)/(1-sin(a)),d*sin(a)/(1-sin(a)))2???$$$!@!@s=Ũ@??????<@X'P;(\Pd*cos(a)/(1-sin(a))d*sin(a)/(1-sin(a))d*cos(a)/(1-sin(a))-dHseg (d*cos(a)/(1-sin(a)),d*sin(a)/(1-sin(a)))--(d*cos(a)/(1-sin(a)),-d)2???$$$!@s=Ũ@??????PTX\ $Di?P`³d*cos(a)/(1-sin(a))d*sin(a)/(1-sin(a))005seg (d*cos(a)/(1-sin(a)),d*sin(a)/(1-sin(a)))--(0,0)2???$$$!@????????!@³PQSTU V d*cos(a)/(1-sin(a))-dpi/4!(x,y) = (d*cos(a)/(1-sin(a)),-d)2???$$$!@??????<@DH Ӵ$Դ(մ xD*#d*cos(a)/(1-sin(a))-d00$seg (d*cos(a)/(1-sin(a)),-d)--(0,0)2???$$$!?????????!? ,ִ=״d*cos(a)/(1-sin(a))/2-d/2pi/4%(x,y) = (d*cos(a)/(1-sin(a))/2,-d/2)2 2??@$$$@???????@ H>PTX\`dKT5,Tĸg,1-D/2+cos(a)/(1-sin(a))*(x-D/2*cos(a)/(1-sin(a)))5y = -D/2+cos(a)/(1-sin(a))*(x-D/2*cos(a)/(1-sin(a)))xyz˖F;??JXT@@h!?@@@@@@@@@@@@@@@@@@@@@@@@@ < < <Directrix"ЀeS4ݵ8ݵR뮻|9&o%E\7Times New RomanݵFocusrixlNYA! "eSЀ޵RXc5Xc%Xb%`oÒA?j1a?Times New RomanԀPcush!?@@@@@@@ " @|G@ncT@Times New RomanMeSxlNYA!@޵eS؁R~ᇟ? 6` ?ӦP bx|Times New RomanDAeSxlNYA!!޵eSRH"$H"@PDEQD@ 1<^0E&)Times New RomanFeSxlNYA!i޵eSHR5\s5//gN, uU?Times New Roman y = -d?@~ᇿ@1Courier Newr = D/(1-sin(t)); 0.000000 <= t <= 6.283190?@|7@1Courier New(y = x^2/(2*D)-D/2?@6h6z@1Courier NewL[(x,y) = (0,0)?@7x׵@1Courier Newy(x,y) = (d*cos(a)/(1-sin(a)),d*sin(a)/(1-sin(a)))?@SN94@1Courier Newseg (d*cos(a)/(1-sin(a)),d*sin(a)/(1-sin(a)))--(d*cos(a)/(1-?@;#<@1Courier NewNseg (d*cos(a)/(1-sin(a)),d*sin(a)/(1-sin(a)))--(0,0)(a)/(1-?@O>@1Courier Newɴ(x,y) = (d*cos(a)/(1-sin(a)),-d)?@鬳:L@1Courier New seg (d*cos(a)/(1-sin(a)),-d)--(0,0)-sin(a)))--(0,0)?@@ )B@1Courier New (x,y) = (d*cos(a)/(1-sin(a))/2,-d/2)YA?@/<3?1Courier NewtSC y = -D/2+cos(a)/(1-sin(a))*(x-D/2*cos(a)/(1-sin(a)))eS@? ?@މ'x?1Courier New