Technical
Help
American Industrial
provides the following technical information in an ongoing effort to provide
technical assistence to persons that have a basic understanding of heat
transfer. As with any engineering disipline, some mathmatical skills are
required to do many of the formulas for calculation that are provided.
It is important that accurate calculations be applied before choosing and
purchasing a heat exchanger. If you are unsure of the proper size of cooler
required, or if you do not understand the formulas contained in the following
subject matter, contact our engineering dapartmant for specific application
help.
Application
Basics
There
are numerous hundreds of applications that heat exchangers can be applied
into, but for the most part only a few configurations come up repeatedly.
Following will describe several configurations for hydraulic, lubrication,
engine coolant, steam heating of liquids, and compressor air cooling. We
can summerize most of the applications into two catagories. The first one
is direct cooling and the second is indirect cooling.
Direct cooling normally applies the heat exchanger directly into the fluid line after it has been heated and before it reaches a reservoir or other device. Normally an example of a direct cooling application would be a cooler in the return line of an open loop hydraulic system. All of the system oil is cooled before it re-enters the reservoir, thus holding the reservoir at a constant temperature. A second example of direct cooling would be in compressed air line exiting a screw compressor. The air is cooled before it enters a receiver tank or the process. In either case it is normally more efficient to cool the oil in this manner since it will allow for greater temperature difference between the fluid being cooled and the coolant.
Examples
Indirect
cooling applies mainly to systems that for good reason (ie..vibration,
pressure, reduced available flow, etc...) cannot directly cool the oil.
This is normally refered to as an off-loop system, 'kidney loop", recirculation
loop, filter loop, etc...., and generally refers to closed loop systems.
Indirect cooling is normally found on mobile equipment or systems with
large flow requirements that make it unrealistic to apply cost effective
cooling. Although the indirect cooling is less efficient than the direct
cooling in many circumstance there is no choice.
Required
information
Regardless of your
application your system will heat one fluid while cooling the other. The
basic theory in heat transfer weather cooling with water or air is "balance",
the equations must balance to produce accurate results. The following information
will help determine many of the required pieces of information needed to
size a heat exchanger to heat or cool your application.
Hydraulic &
Lubrication Systems
1) Electric
motor horsepower of prime mover pump or heat to be removed if known. If
more than one prime mover, add them up.
2) System
(oil) operating pressure.
3) Process
(oil) system flow rate or flow rate to heat exchanger.
4) Process
(oil) temperature entering or exiting the heat exchanger or desired reservoir
temperature.
5) Oil
type. (ISO 32, 46, 68, etc...)
6) Cooling
media. (water, air)
7) Average
cooling media temperature & worse case temperature. (ie.. 100F air,
95F water, etc...)
8) Available
volume cooling media. ( 10gpm, 20 gpm, 30gpm, etc...)
9) Material
requirements.
10) Physical
size requirements.
11) If
air cooled, fan drive. ( Electric, hydraulic, pneumatic, etc...)
12) Location
of cooler. (Return line, off loop)
Steam Heating
1) Type
of fluid to be heated. If exotic obtain specific heat transfer information
such as, specific heat, conductivity, viscosity, and density.
2) Beginning
& ending temperatures of fluid to be heated.
3) Flow
rate of fluid to be heated.
4) Operating
pressure of saturated steam in PSI.
Shell & Tube
Step1.
Industrial Formula
Example
Electric
motor prime mover HP x .3 = HP heat
40 HPelectric x .3 = 12 HP heat
Mobile Formula
Example
Main system
flow GPM x operating pressure PSI
23 gpm x 3000 psi
-------------------------------------------------------------------
X .3 = HP heat
------------------------- X .3 = 12 HP
1714
1714
HP x 2545
= BTU/hr heat
12 x 2545 = 30,540 BTU/hr
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